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Potential energy of the mass at a height above the earth's surface is given by `=(75)/(100)xx12=9 J`………(i) <br> Now, KE of the mass at the end of fall `KE=(1)/(2)mv^(2)`……….(ii) <br> Applying law of conservation of energy, <br> `(1)/(2)mv^(2)=9impliesv=sqrt((2xx9)/(m))sqrt((18)/(1))=sqrt(18) ms^(-1)`